分解因式:(2x 3)的两次方-9(x-1)的两次方
发布网友
共3个回答
热心网友
如：A:
(2X-3)^2-9(X-1)^2
=(2X-3)^2-(3(X-1))^2
=(2X-3)^2-(3X-3)^2
=((2X-3)+(3X-3))((2X-3)-(3X-3))
=(5X-6)(-X)
=-X(5X-6)
如：B:
(2X+3)^2-9(X-1)^2
=(2X+3)^2-(3(X-1))^2
=(2X+3)^2-(3X-3)^2
=((2X+3)+(3X-3))((2X+3)-(3X-3))
=5X(-X+6)
=5X(6-X)
总结：A^2-B^2=(A+B)(A-B)
热心网友
(2x+3)²-9(x-1)²
=(2x+3)²-[3(x-1)]²
=[(2x+3)+3(x-1)][(2x+3)-3(x-1)]
=(2x+3+3x-3)(2x+3-3x+3)
=5x(-x+6)
=-5x(x-6)
热心网友
(2x 3)是啥
麻烦核对一下
