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M13 := MA(C, 13);
M15 := MA(C, 15);
SC13 := O<=M13 AND C>M13;
SC15 := O<=M15 AND C>M15;
ZP13 := M13 >= REF(M13, 1);
ZP15 := M15 >= REF(M15, 1);
C135 := CROSS(M13, M15);
XG: SC13 AND SC15 AND ZP13 AND ZP15 AND C135;
{评测结果,持有一天胜率53%}追问咋有135啊
追答代号,13上穿15